How is this calculated?
The math continuously tracks how strongly this post is connected to the rest of the network. Every tag forms a 2-way link. The base stats determine personal node strength, and the pie charts below show this node's share against its direct neighbours.
// 1. Base variables (floored at 1 to prevent zero-multiplication math errors)
$inbound = max(1, 2) = 2
$outbound = max(1, 2) = 2
// 2. Node Base Values (Local connection strength)
Base_Strength (PV) = $inbound * $outbound = 2 * 2 = 4
Base_Influence (IV) = $inbound / $outbound = 2 / 2 = 1
// 3. Exponential Network Values (accumulating 20 direct neighbours)
Network_Strength (CV) = Base_PV * (Neighbour_1_PV * Neighbour_2_PV * ...)
= 4 *
( 25 [John Sessions] *
1 [Hugh Dennis] *
16 [Tony Hendra] *
361 [Spitting Image] *
25 [Alistair McGowan] *
25 [Chris Barrie] *
1 [Chris Emmett] *
4 [Enn Reitel] *
25 [Harry Enfield] *
1 [Jessica Martin] *
1 [John Thomson] *
1 [Jon Culshaw] *
16 [Jon Glover] *
25 [Kate Robbins] *
1 [Louise Gold] *
1 [Mark Alexander Todd] *
4 [Steve Coogan] *
1 [Roger Blake] *
1 [Steve Nallon] *
1 [Dead Ringers (5)]
)
= 57.76T
Network_Influence (TV) = Base_IV * (Neighbour_1_IV * Neighbour_2_IV * ...)
= 1 *
( 1 [John Sessions] *
1 [Hugh Dennis] *
1 [Tony Hendra] *
1 [Spitting Image] *
1 [Alistair McGowan] *
1 [Chris Barrie] *
1 [Chris Emmett] *
1 [Enn Reitel] *
1 [Harry Enfield] *
1 [Jessica Martin] *
1 [John Thomson] *
1 [Jon Culshaw] *
1 [Jon Glover] *
1 [Kate Robbins] *
1 [Louise Gold] *
1 [Mark Alexander Todd] *
1 [Steve Coogan] *
1 [Roger Blake] *
1 [Steve Nallon] *
1 [Dead Ringers (5)]
)
= 1
Outbound
2
Tags on post
Inbound
2
Posts tagging this
Connections
20
Total nodes
Base Node Strength
4
Base Node Influence
1
Strength Share (vs Direct Neighbours)
Dominant nodes (excluded from chart)Spitting Image 66.85%John Sessions 4.63%Alistair McGowan 4.63%Chris Barrie 4.63%Harry Enfield 4.63%Kate Robbins 4.63%
Influence Share (vs Direct Neighbours)
Connected Network Hierarchy
Sort list by:
Connection Health Audit (Red = broken 1-way link)