How is this calculated?
The math continuously tracks how strongly this post is connected to the rest of the network. Every tag forms a 2-way link. The base stats determine personal node strength, and the pie charts below show this node's share against its direct neighbours.
// 1. Base variables (floored at 1 to prevent zero-multiplication math errors)
$inbound = max(1, 1) = 1
$outbound = max(1, 1) = 1
// 2. Node Base Values (Local connection strength)
Base_Strength (PV) = $inbound * $outbound = 1 * 1 = 1
Base_Influence (IV) = $inbound / $outbound = 1 / 1 = 1
// 3. Exponential Network Values (accumulating 17 direct neighbours)
Network_Strength (CV) = Base_PV * (Neighbour_1_PV * Neighbour_2_PV * ...)
= 1 *
( 289 [Bloodbound] *
1 [Anders Broman] *
1 [Henrik Olsson] *
1 [Tomas Olsson] *
4 [Patrik Johansson] *
25 [Urban Breed] *
225 [Michael Bormann] *
16 [Urban Breed (2)] *
1 [Henrik Olsson (2)] *
1 [Johan Sohlberg] *
9 [Markus Albertson] *
1 [Tomas Olsson (2)] *
1 [Bloodbound - Masters of Rock 2018] *
1 [Bloodbound - Noch ein Bier Fest 2015] *
36 [Pelle Åkerlind] *
1 [Daniel Sjögren (2)] *
1 [Pelle Ã
kerlind]
)
= 33.71B
Network_Influence (TV) = Base_IV * (Neighbour_1_IV * Neighbour_2_IV * ...)
= 1 *
( 1 [Bloodbound] *
1 [Anders Broman] *
1 [Henrik Olsson] *
1 [Tomas Olsson] *
1 [Patrik Johansson] *
1 [Urban Breed] *
1 [Michael Bormann] *
1 [Urban Breed (2)] *
1 [Henrik Olsson (2)] *
1 [Johan Sohlberg] *
1 [Markus Albertson] *
1 [Tomas Olsson (2)] *
1 [Bloodbound - Masters of Rock 2018] *
1 [Bloodbound - Noch ein Bier Fest 2015] *
1 [Pelle Åkerlind] *
1 [Daniel Sjögren (2)] *
1 [Pelle Ã
kerlind]
)
= 1
Outbound
1
Tags on post
Inbound
1
Posts tagging this
Connections
17
Total nodes
Base Node Strength
1
Base Node Influence
1
Strength Share (vs Direct Neighbours)
Dominant nodes (excluded from chart)Bloodbound 46.99%Michael Bormann 36.59%Pelle Åkerlind 5.85%Urban Breed 4.07%Urban Breed (2) 2.60%
Influence Share (vs Direct Neighbours)
Connected Network Hierarchy
Sort list by:
Connection Health Audit (Red = broken 1-way link)