How is this calculated?
The math continuously tracks how strongly this post is connected to the rest of the network. Every tag forms a 2-way link. The base stats determine personal node strength, and the pie charts below show this node's share against its direct neighbours.
// 1. Base variables (floored at 1 to prevent zero-multiplication math errors)
$inbound = max(1, 1) = 1
$outbound = max(1, 1) = 1
// 2. Node Base Values (Local connection strength)
Base_Strength (PV) = $inbound * $outbound = 1 * 1 = 1
Base_Influence (IV) = $inbound / $outbound = 1 / 1 = 1
// 3. Exponential Network Values (accumulating 22 direct neighbours)
Network_Strength (CV) = Base_PV * (Neighbour_1_PV * Neighbour_2_PV * ...)
= 1 *
( 80 [Brian Harris] *
16 [Davey Traynor] *
9 [Cahir O'Doherty] *
4 [Gerry Neil] *
36 [Shay Murphy] *
4 [Scott Mulvey] *
25 [Gerry Mulryan] *
25 [Liam McKenna] *
81 [Kevin McAlea] *
9 [Norman Lindsay] *
16 [Ernie Durkin] *
1 [Mervyn Doyle] *
81 [Brian Donaghy] *
49 [Greg Donaghey] *
36 [Donie Devaney] *
64 [Noel Bridgeman] *
4 [Seamus Caulfield] *
484 [Gentry] *
1 [Aiden Hand] *
4 [Davy Traynor] *
1 [Ronnie Souter] *
4 [Gerry Carr]
)
= 1.37 x 10^25
Network_Influence (TV) = Base_IV * (Neighbour_1_IV * Neighbour_2_IV * ...)
= 1 *
( 1.25 [Brian Harris] *
1 [Davey Traynor] *
1 [Cahir O'Doherty] *
1 [Gerry Neil] *
1 [Shay Murphy] *
1 [Scott Mulvey] *
1 [Gerry Mulryan] *
1 [Liam McKenna] *
1 [Kevin McAlea] *
1 [Norman Lindsay] *
1 [Ernie Durkin] *
1 [Mervyn Doyle] *
1 [Brian Donaghy] *
1 [Greg Donaghey] *
1 [Donie Devaney] *
1 [Noel Bridgeman] *
1 [Seamus Caulfield] *
1 [Gentry] *
1 [Aiden Hand] *
1 [Davy Traynor] *
1 [Ronnie Souter] *
1 [Gerry Carr]
)
= 1.25
Outbound
1
Tags on post
Inbound
1
Posts tagging this
Connections
22
Total nodes
Base Node Strength
1
Base Node Influence
1
Strength Share (vs Direct Neighbours)
0.10%
(1.37 × 1025 overall)
Dominant nodes (excluded from chart)Gentry 46.76%
Influence Share (vs Direct Neighbours)
Connected Network Hierarchy
Sort list by:
Connection Health Audit (Red = broken 1-way link)