How is this calculated?
The math continuously tracks how strongly this post is connected to the rest of the network. Every tag forms a 2-way link. The base stats determine personal node strength, and the pie charts below show this node's share against its direct neighbours.
// 1. Base variables (floored at 1 to prevent zero-multiplication math errors)
$inbound = max(1, 2) = 2
$outbound = max(1, 2) = 2
// 2. Node Base Values (Local connection strength)
Base_Strength (PV) = $inbound * $outbound = 2 * 2 = 4
Base_Influence (IV) = $inbound / $outbound = 2 / 2 = 1
// 3. Exponential Network Values (accumulating 19 direct neighbours)
Network_Strength (CV) = Base_PV * (Neighbour_1_PV * Neighbour_2_PV * ...)
= 4 *
( 81 [Nero and the Gladiators] *
9 [Tony Harvey] *
4 [Ralph Danks] *
16 [Rod 'Boots' Slade] *
1 [Mike O'Neill (2)] *
1 [Colin Green (2)] *
1 [Ray Miles (3)] *
4 [Rod Slade] *
1 [Tommy Brown (3)] *
256 [Mick Jones] *
1 [Boots Slade] *
64 [Joe Moretti] *
4 [Laurie Jay] *
169 [Nero & The Gladiators] *
1 [Colin Green] *
64 [Diz Disley] *
1 [Jim Cannon] *
4 [Mike O'Neill] *
1 [Tommy Brown]
)
= 2.12 x 10^15
Network_Influence (TV) = Base_IV * (Neighbour_1_IV * Neighbour_2_IV * ...)
= 1 *
( 1 [Nero and the Gladiators] *
1 [Tony Harvey] *
1 [Ralph Danks] *
1 [Rod 'Boots' Slade] *
1 [Mike O'Neill (2)] *
1 [Colin Green (2)] *
1 [Ray Miles (3)] *
1 [Rod Slade] *
1 [Tommy Brown (3)] *
1 [Mick Jones] *
1 [Boots Slade] *
1 [Joe Moretti] *
1 [Laurie Jay] *
1 [Nero & The Gladiators] *
1 [Colin Green] *
1 [Diz Disley] *
1 [Jim Cannon] *
1 [Mike O'Neill] *
1 [Tommy Brown]
)
= 1
Outbound
2
Tags on post
Inbound
2
Posts tagging this
Connections
19
Total nodes
Base Node Strength
4
Base Node Influence
1
Strength Share (vs Direct Neighbours)
0.58%
(2.12 × 1015 overall)
Dominant nodes (excluded from chart)Mick Jones 37.26%Nero & The Gladiators 24.60%Nero and the Gladiators 11.79%Joe Moretti 9.32%Diz Disley 9.32%
Influence Share (vs Direct Neighbours)
Connected Network Hierarchy
Sort list by:
Connection Health Audit (Red = broken 1-way link)