How is this calculated?
The math continuously tracks how strongly this post is connected to the rest of the network. Every tag forms a 2-way link. The base stats determine personal node strength, and the pie charts below show this node's share against its direct neighbours.
// 1. Base variables (floored at 1 to prevent zero-multiplication math errors)
$inbound = max(1, 8) = 8
$outbound = max(1, 5) = 5
// 2. Node Base Values (Local connection strength)
Base_Strength (PV) = $inbound * $outbound = 8 * 5 = 40
Base_Influence (IV) = $inbound / $outbound = 8 / 5 = 1.6
// 3. Exponential Network Values (accumulating 5 direct neighbours)
Network_Strength (CV) = Base_PV * (Neighbour_1_PV * Neighbour_2_PV * ...)
= 40 *
( 1 [Art in the London Borough of Harrow] *
1 [Food in the London Borough of Harrow] *
1 [Sports in the London Borough of Harrow] *
1 [Statistics of the London Borough of Harrow] *
1 [Visitor attractions in the London Borough of Harrow]
)
= 40
Network_Influence (TV) = Base_IV * (Neighbour_1_IV * Neighbour_2_IV * ...)
= 1.6 *
( 1 [Art in the London Borough of Harrow] *
1 [Food in the London Borough of Harrow] *
1 [Sports in the London Borough of Harrow] *
1 [Statistics of the London Borough of Harrow] *
1 [Visitor attractions in the London Borough of Harrow]
)
= 1.6
Outbound
8
Tags on post
Inbound
5
Posts tagging this
Connections
5
Total nodes
Base Node Strength
40
Base Node Influence
1.6
Strength Share (vs Direct Neighbours)
Influence Share (vs Direct Neighbours)
Connected Network Hierarchy
Sort list by:
Connection Health Audit (Red = broken 1-way link)
Flags in the London Borough of Harrow
BROKEN LINKHousing in the London Borough of Harrow
BROKEN LINKStructures in the London Borough of Harrow
BROKEN LINK
