How is this calculated?
The math continuously tracks how strongly this post is connected to the rest of the network. Every tag forms a 2-way link. The base stats determine personal node strength, and the pie charts below show this node's share against its direct neighbours.
// 1. Base variables (floored at 1 to prevent zero-multiplication math errors)
$inbound = max(1, 5) = 5
$outbound = max(1, 4) = 4
// 2. Node Base Values (Local connection strength)
Base_Strength (PV) = $inbound * $outbound = 5 * 4 = 20
Base_Influence (IV) = $inbound / $outbound = 5 / 4 = 1.25
// 3. Exponential Network Values (accumulating 20 direct neighbours)
Network_Strength (CV) = Base_PV * (Neighbour_1_PV * Neighbour_2_PV * ...)
= 20 *
( 6 [the Weeknd] *
42 [Florence + The Machine] *
56 [Mike Dean] *
110 [Borealis] *
306 [Broadcast News] *
1 [Lana Del Rey album art] *
4 [I Am Number Four] *
16 [Elizabeth Debicki] *
25 [Lois Chiles] *
16 [Max Cullen] *
289 [Guardians of the Galaxy Vol. 2] *
361 [The Man from U.N.C.L.E.] *
256 [Widows] *
289 [The Way We Were] *
9 [Death on the Nile] *
289 [Creepshow 2] *
324 [Spyforce] *
36 [X-Men Origins: Wolverine] *
324 [Love My Way] *
6 [Jamie Smith]
)
= 1.11 x 10^35
Network_Influence (TV) = Base_IV * (Neighbour_1_IV * Neighbour_2_IV * ...)
= 1.25 *
( 1.5 [the Weeknd] *
1.17 [Florence + The Machine] *
1.14 [Mike Dean] *
1.1 [Borealis] *
1.06 [Broadcast News] *
1 [Lana Del Rey album art] *
1 [I Am Number Four] *
1 [Elizabeth Debicki] *
1 [Lois Chiles] *
1 [Max Cullen] *
1 [Guardians of the Galaxy Vol. 2] *
1 [The Man from U.N.C.L.E.] *
1 [Widows] *
1 [The Way We Were] *
1 [Death on the Nile] *
1 [Creepshow 2] *
1 [Spyforce] *
1 [X-Men Origins: Wolverine] *
1 [Love My Way] *
0.6667 [Jamie Smith]
)
= 1.94
Outbound
5
Tags on post
Inbound
4
Posts tagging this
Connections
20
Total nodes
Base Node Strength
20
Base Node Influence
1.25
Strength Share (vs Direct Neighbours)
0.72%
(1.11 × 1035 overall)
Influence Share (vs Direct Neighbours)
Connected Network Hierarchy
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Connection Health Audit (Red = broken 1-way link)